complex numbers multiple choice questions with answers pdf

You can also have online access to Engineering Maths Multiple Choice Questions Answers EBook. 1Now, equation 1 is imaginary if3 – 4sin² θ = 0⇒ 4sin² θ = 3⇒ sin² θ = 3/4⇒ sin θ = ±√3/2⇒ θ = nπ ± π/3 where n is an integer, Question 14.If {(1 + i)/(1 – i)}n = 1 then the least value of n is(a) 1(b) 2(c) 3(d) 4, Answer: (d) 4Hint:Given, {(1 + i)/(1 – i)}n = 1⇒ [{(1 + i) × (1 + i)}/{(1 – i) × (1 + i)}]n = 1⇒ [{(1 + i)²}/{(1 – i²)}]n = 1⇒ [(1 + i² + 2i)/{1 – (-1)}]n = 1⇒ [(1 – 1 + 2i)/{1 + 1}]n = 1⇒ [2i/2]n = 1⇒ in = 1Now, in is 1 when n = 4So, the least value of n is 4, Question 15.If arg (z) < 0, then arg (-z) – arg (z) =(a) π(b) -π(c) -π/2(d) π/2, Answer: (a) πHint:Given, arg (z) < 0Now, arg (-z) – arg (z) = arg(-z/z)⇒ arg (-z) – arg (z) = arg(-1)⇒ arg (-z) – arg (z) = π {since sin π + i cos π = -1, So arg(-1) = π}, Question 16.if x + 1/x = 1 find the value of x2000 + 1/x2000 is(a) 0(b) 1(c) -1(d) None of these, Answer: (c) -1Hint:Given x + 1/x = 1⇒ (x² + 1) = x⇒ x² – x + 1 = 0⇒ x = {-(-1) ± √(1² – 4 × 1 × 1)}/(2 × 1)⇒ x = {1 ± √(1 – 4)}/2⇒ x = {1 ± √(-3)}/2⇒ x = {1 ± √(-1)×√3}/2⇒ x = {1 ± i√3}/2 {since i = √(-1)}⇒ x = -w, -w²Now, put x = -w, we getx2000 + 1/x2000 = (-w)2000 + 1/(-w)2000= w2000 + 1/w2000= w2000 + 1/w2000= {(w³)666 × w²} + 1/{(w³)666 × w²}= w² + 1/w² {since w³ = 1}= w² + w³ /w²= w² + w= -1 {since 1 + w + w² = 0}So, x2000 + 1/x2000 = -1, Question 17.The value of √(-144) is(a) 12i(b) -12i(c) ±12i(d) None of these, Answer: (a) 12iHint:Given, √(-144) = √{(-1)×144}= √(-1) × √(144)= i × 12 {Since √(-1) = i}= 12iSo, √(-144) = 12i, Question 18.If the cube roots of unity are 1, ω, ω², then the roots of the equation (x – 1)³ + 8 = 0 are(a) -1, -1 + 2ω, – 1 – 2ω²(b) – 1, -1, – 1(c) – 1, 1 – 2ω, 1 – 2ω²(d) – 1, 1 + 2ω, 1 + 2ω², Answer: (c) – 1, 1 – 2ω, 1 – 2ω²Hint:Note that since 1, ω, and ω² are the cube roots of unity (the three cube roots of 1), they are the three solutions to x³ = 1 (note: ω and ω² are the two complex solutions to this)If we let u = x – 1, then the equation becomesu³ + 8 = (u + 2)(u² – 2u + 4) = 0.So, the solutions occur when u = -2 (giving -2 = x – 1 ⇒ x = -1), or when:u² – 2u + 4 = 0,which has roots, by the Quadratic Formula, to be u = 1 ± i√3So, x – 1 = 1 ± i√3⇒ x = 2 ± i√3Now, x³ = 1 when x³ – 1 = (x – 1)(x² + x + 1) = 0, giving x = 1 andx² + x + 1 = 0⇒ x = (-1 ± i√3)/2If we let ω = (-1 – i√3)/2 and ω₂ = (-1 + i√3)/2then 1 – 2ω and 1 – 2ω² yield the two complex solutions to (x – 1)³ + 8 = 0So, the roots of (x – 1)³ + 8 are -1, 1 – 2ω, and 1 – 2ω², Question 19. शिक्षण प्रक्रिया में शिक्षक को अनेक कार्य एक साथ करने पड़ते हैं जैसे लिखना, प्रश्न पूछना, स्पष्ट करना, प्रदर्शन करना... शिक्षण कौशल ( Teaching Skill) Find all complex numbers z such that z 2 = -1 + 2 sqrt(6) i. If you searching to check on Complex Numbers Multiple Choice Pdf And Income Tax Multiple Choice Questions And Answers Pdf price. a) Find b and c b) Write down the second root and check it. But first equality of complex numbers must be defined. A card is taken out from the bag at random. 9. Check the below NCERT MCQ Questions for Class 11 Maths Chapter 5 Complex Numbers and Quadratic Equations with Answers Pdf free download. 3 - (-2+3i) + (-5+i) = ? Start below. Answer: d Explaination: Reason: Total cards = 18 Click here to join our FB Page and FB Group for Latest update and preparation tips and queries. You can skip questions if … Find the absolute value of complex numbers outlined in the quiz. � : : : �. . EMBED Equation.3 45 27 9 + 36i -27 - 36i 5. Get Chapter Wise MCQ Questions for Class 11 Maths with Answers PDF Free Download prepared here according to the latest CBSE syllabus and NCERT curriculum. (3i)(2i) 6i -6i 6 -6 8. C ell references but not values d. Value and cell references Q. h &� CJ UVaJ j h &� h &� EH��UjQ@yP MCQ Questions for Class 11 Maths with Answers were prepared based on the latest exam pattern. 2 - 2i c. -2i d. 2i 2. Students can practice CBSE Class 11 Maths MCQs Multiple Choice Questions with Answers to score good marks in the examination. (1 – w + w²)×(1 – w² + w4)×(1 – w4 + w8) × …………… to 2n factors is equal to(a) 2n(b) 22n(c) 23n(d) 24n, Answer: (b) 22nHint:Given, (1 – w + w²)×(1 – w² + w4)×(1 – w4 + w8) × …………… to 2n factors= (1 – w + w2)×(1 – w2 + w )×(1 – w + w2) × …………… to 2n factors{Since w4 = w, w8 = w2}= (-2w) × (-2w²) × (-2w) × (-2w²)× …………… to 2n factors= (2² w³)×(2² w³)×(2² w³) …………… to 2n factors= (2²)n {since w³ = 1}= 22n, Question 20.The modulus of 5 + 4i is(a) 41(b) -41(c) √41(d) -√41, Answer: (c) √41Hint:Let Z = 5 + 4iNow modulus of Z is calculated as|Z| = √(5² + 4²)⇒ |Z| = √(25 + 16)⇒ |Z| = √41So, the modulus of 5 + 4i is √41. . Y, � ,2 � � ,2 4 �- ,2 � �- 8 : : � : : : : : 9. The complex number 2 + 4i is one of the root to the quadratic equation x 2 + bx + c = 0, where b and c are real numbers. Find the product of 4 + i and 4 � i 15 17 EMBED Equation.3 16 4. ... Then multiply the number by its complex conjugate. 1. Then(a) a² = b(b) a² = 2b(c) a² = 3b(d) a² = 4b, Answer: (c) a² = 3bHint:Given, z1 and z2 be two roots of the equation z² + az + b = 0Now, z1 + z2 = -a and z1 × z2 = bSince z1 and z2 and z3 from an equilateral triangle.⇒ z12 + z22 + z32 = z1 × z2 + z2 × z3 + z1 × z3⇒ z12+ z22 = z1 × z2 {since z3 = 0}⇒ (z1 + z2)² – 2z1 × z2 = z1 × z2⇒ (z1 + z2)² = 2z1 × z2 + z1 × z2⇒ (z1 + z2)² = 3z1 × z2⇒ (-a)² = 3b⇒ a² = 3b, Question 10:The complex numbers sin x + i cos 2x are conjugate to each other for(a) x = nπ(b) x = 0(c) x = (n + 1/2) π(d) no value of x, Answer: (d) no value of xHint:Given complex number = sin x + i cos 2xConjugate of this number = sin x – i cos 2xNow, sin x + i cos 2x = sin x – i cos 2x⇒ sin x = cos x and sin 2x = cos 2x {comparing real and imaginary part}⇒ tan x = 1 and tan 2x = 1Now both of them are not possible for the same value of x.So, there exist no value of x, Question 11.The curve represented by Im(z²) = k, where k is a non-zero real number, is(a) a pair of striaght line(b) an ellipse(c) a parabola(d) a hyperbola. Don’t let the question position or question type deter you from answering questions. 2) - 9 2) It is reflects Algebra 2 (algebra ii) level exercises. Download JEE Mathematics Complex Numbers MCQs Set A in pdf, Complex Numbers chapter wise Multiple Choice Questions free. a. h &� CJ UVaJ j h &� UhH h &� # 4 5 8 : @ A ] ^ a y � � � � � � � � � � � � � � � � � � � � � � � � � � � � � � � � � � � � � � addition, multiplication, division etc., need to be defined. 10. A complex number is usually denoted by the letter ‘z’. 5 cis 36.87 b. Engineering Maths Objective type Questions Answers are also used at SSC and HSc level for Exam preparation. Having introduced a complex number, the ways in which they can be combined, i.e. Choose the one alternative that best completes the statement or answers the question. � �� $ � �. In addition to the questions in Heart of Algebra, Problem Solving and Data Analysis, and Passport to Advanced Math, the SAT Math Test includes several questions that are drawn from areas of geometry, trigonometry, and the arithmetic of complex numbers. Where can you find best quality multiple choice questions? 1. Answer/ Explanation. EMBED Equation.3 8i -8i 6i -6i 9. Multiple choice questions on number system quiz answers PDF covers MCQ questions on topics: Properties of real numbers, rational numbers, irrational numbers, complex numbers, basic function, binary operation, De Moivre’s theorem, groups, linear and quadratic function, sets, operation on three sets, and relation. � : . All quizzes are paired with a … Practice the multiple choice questions to test understanding of important topics in the chapters. Please note that, as on the actual test form, approximately one third of the multiple-choice questions in this test guide are more complex questions that require 2–3 minutes The section contains questions on deMoivre’s theorem, trigonometric functions expansion, complex conjugates, complex plane regions, complex numbers logarithm, powers and roots. ‘a’ is called the real part, and ‘b’ is called the imaginary part of the complex number. 2+2i b. : : : : � � � d � � � � � � � � � � � � � �� Complex Numbers Quiz 2 1. To Test understanding of complex numbers outlined in the chapters with Answers score! Assume that the origin, z1 and z1 form an equilateral triangle ) find b and c b write. Important topics in the quiz last within each group of multiple-choice questions and within..., but using i 2 =−1 where appropriate @ 0�v�� t ^?.! Your Answers to the questions and Answers Pdf price, Engineering and Medical entrance exams that... 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